2[3-2(2+4)]=3(4-2)

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Solution for 2[3-2(2+4)]=3(4-2) equation:


Simplifying
2[3 + -2(2 + 4)] = 3(4 + -2)

Combine like terms: 2 + 4 = 6
2[3 + -2(6)] = 3(4 + -2)

Multiply -2 * 6
2[3 + -12] = 3(4 + -2)

Combine like terms: 3 + -12 = -9
2[-9] = 3(4 + -2)

Multiply 2 * -9
-18 = 3(4 + -2)

Combine like terms: 4 + -2 = 2
-18 = 3(2)

Multiply 3 * 2
-18 = 6

Solving
-18 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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